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d^2+12d-864=0
a = 1; b = 12; c = -864;
Δ = b2-4ac
Δ = 122-4·1·(-864)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-60}{2*1}=\frac{-72}{2} =-36 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+60}{2*1}=\frac{48}{2} =24 $
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